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Quadratic Equation Practice set 1 for IBPS Clerk 2017

Quadratic Equation Practice set 1 for IBPS Clerk 2017



1 .Directions (Q. Nos. 1-5) : In the following questions two equations numbered I and II are given. You have to solve both the equations and— 
Give answer 
(1) if x > y 
(2) if x  y 
(3) if x < y
(4) if x  y 
(5) if x = y or the relationship cannot be established

Q.
I. 1225x+4900=0 
II. (81)14y+(343)13=0
A). x>y
B). x<y
C). xy
D). xy
Answer & Explanation
Answer : Option A
Explanation :
I. 1225x+4900=0
35x + 70 = 0
x = - 7035 = -2

II. 3y + 7 = 0 
y = - 73

x>y
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2 .I. 18x2 + 6x2 - 12x2 = 8x2 
II. y3 + 9.68 + 5.64 = 16.95
A). x>y
B). xy
C). xy
D). x = y or no relation can be established between ‘x’ and ‘y’.
Answer & Explanation
Answer : Option D
Explanation :
I. 18+6x12x2 = 8x2
or , x = 13 = 0.333

II. y2 = 16.95 - 9.68 - 5.64 = 1.63
y = ±1.277
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3 .I. (2)5+(11)36 = x3 
II. 4y3=(589÷4)+5y3
A). x>y
B). xy
C). x<y
D). xy
Answer & Explanation
Answer : Option A
Explanation :
I. x3= 32+13316 = 13636
II. 5y34y3= 5894
or y3= 5894

x>y
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4 .I. 12x2 + llx + 12 = 10x 2 +22x
II. 13y2 - 18y + 3 = 9y 2 - 10y
A). x>y
B). xy
C). x<y
D). xy
Answer & Explanation
Answer : Option B
Explanation :
I. 2x2 - llx + 12 = 0
or, x = 4, 32

II. 4y2 - 8y + 3 = 0
y = 32 , 12

xy
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5 .I. (x75÷9) = 169÷y35
II. y14×y14×7 = 273÷y12
A). x>y
B). xy
C). x<y
D). xy
View Answer

6 .Directions (Q. 6 - 10): Two equations (I) and (II) are given in each question. On the basis of these equations you have to decide the relation between x and y and give answer

(1) if x > y 
(2) if x < y 
(3) if x  y 
(4) if x  y
(5) if x = y, or no relation can be established between x and y.

Q. 
I. x = 24014
II.2y2 - 9y - 56 = 0
A). x>y
B). x<y
C). xy
D). x = y or no relation can be established between ‘x’ and ‘y’.
Answer & Explanation
Answer : Option D
Explanation :
I. x = 24014
 x = 7 

II.2y2 - 16y + 7y - 56 = 0
2y(y - 8) + 7(y - 8) = 0
(2y + 7) (y - 8) = 0
y = 8 , - 72

Hence, no relation exists between x and y.
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7 .I. 5x2 + 3x - 14 = 0
II.2y2 - 9y + 10 = 0
A). x>y
B). x<y
C). xy
D). xy
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8 .I. 8x2 + 31x + 21 = 0 
II. 5y2 + 11y - 36 = 0
A). x>y
B). x<y
C). xy
D). x = y or no relation can be established between ‘x’ and ‘y’.
Answer & Explanation
Answer : Option D
Explanation :
I. 8x2 + 24x + 7x + 21 = 0
or, 8x(x + 3) + 7(x + 3) = 0
or, (x + 3) (8x + 7) = 0
x = - 3, - 78

II. 5y2 + 20y - 9y - 36 = 0
or, 5y(y + 4) - 9(y + 4) = 0
or, (y + 4) (5y - 9) = 0
y = -4, 95 

Hence, no relation exists between x and y.
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9 .I. 3x - y = 12 
II. y = 1089
A). x>y
B). x<y
C). xy
D). xy
Answer & Explanation
Answer : Option B
Explanation :
I. y = 1089  y = 33

II. x = 12+y3 = 12+333 = 453 = 15 

x<y
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10 .I. 15x2 + 68x + 77 = 0 
II. 3y2 + 29y + 68 = 0
A). x>y
B). x<y
C). xy
D). xy
Answer & Explanation
Answer : Option A
Explanation :
I. 15x2 + 68x + 77 = 0
or, 15x2 + 35x + 33x + 77 = 0
or, 5x(3x + 7) + 11(3x + 7) = 0
or, (5x + 11) (3x + 7) = 0
x = -73 , -115

II. 3y2 + 29y + 68 = 0
or, 3y2 + 12y + 17y + 68 = 0
or, 3y(y + 4) + 17(y + 4) = 0
or, (y + 4) (3y + 17) = 0
y = -4, -173

x>y
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