Government of India, Nuclear Power Corporation of India Limited (NPCIL) has published a notification for the recruitment of Stipendiary Trainee vacancies. Eligible Indian Nationals may apply on or before 21-12-2017. Other details like age limit, educational qualification, selection process & how to apply are given below…
NPCIL Vacancy Details: Total No. of Posts: 02 Name of the Post: Stipendiary Trainee/ Scientific Assistant (Health Physics)
Age Limit: Candidates age should be 18-25 years as on 21-12-2017. Age relaxation is applicable as per rules.
Educational Qualification: Candidates should possess B.Sc. with a minimum of 60% marks, B.Sc with Physics as principal and Chemistry/ Mathematics/ Statistics/ Electronics & Computer Science as subsidiary or with Chemistry as principal and Physics/ Mathematics/ Statistics/ Electronics & Computer Science as subsidiary or with Physics, Chemistry and Mathematics as subjects with equal weightage, Mathematics at H.S.C. (10+2) level.
Selection Process: Selection will be based on Written Examination & Personal Interview.
How to Apply: Eligible candidates can send their application in the prescribed format along with self attested photo copies of Educational qualification, experience certificates (if any), Community certificate, Copy of the judgement /decree of the appropriate court (if applicable) & 02 Recent Passport size photograph by ordinary post to Manager (HRM), Kaiga Site, Nuclear Power Corporation of India Limited (NPCIL), PO: Kaiga, via: Karwar, Uttara Kannada District, Karnataka State, PIN- 581 400 on or before 21-12-2017. Superscribe the envelope with “Application for the post of —–”.
Last Date for Receipt of Application: 21-12-2017
For more details like Physical Standards, Training Duration, stipend & other information click on the link given below…